Percentage Questions Basic

Solution:

20% of a=b ⇒ (20/100)a=b → b% of 20→ (b/100)×20 = (4/100)a = 4% of a

Solution:

5 % of A+4% of B =(2/3) (6% of A+8% of B)

⇒(5/100)A+(4/100)B=2/3(6/100A+8/100B) 

⇒(1/20−1/25)A=(4/75−1/25)B→A/B=100/75=4/3

Solution: 

Let M be the maximum marks of the exam. 

Let P be the passing marks. According to the given conditions, 

Candidate A gets 20% marks and fails by 10 marks. 

So, (20/100)M = P - 10 

=> P = (20/100)M + 10. Candidate B gets 42% marks and gets 12% more than the passing marks. 

So, (42/100)M = P + (12/100)P 

=> (42/100)M = P(1 + 12/100) 

=> P = (42/112)M. Equating the values of P from both equations, we get: (20/100)M + 10 = (42/112)M 

=> 56M = 1000 

=> M = 1000/56 

=> M = 17.86 ≈ 18 (approx) . Therefore, the maximum marks of the exam is  100 (option B)

Solution:

Given: S = 150% of T 

S=150/100T=3/2T 

S + T= 5/2T 

T=2/5 (S+T) = 40% of (S+T)

Solution:

A = 2B , B = 3C/5, C = 5B/3, E = 1.9A = 3.8B , D = E/2 = 1.9 B 

Therefore, B weighs the least.

Solution:

Let the amount of taxable purchases be Rs.x. Given, 6% of x=30 paisa = Rs  30/100 

X = (30/100×100/6) = 5  

Cost of tax free items = Rs [25−(5+0.30)] =Rs.19.70 

Solution:

Each boundary is worth 4 runs, and each six is worth 6 runs. So the runs  scored from boundaries and sixes are: 

        i.  3 boundaries x 4 runs/boundary = 12 runs

ii. 8 sixes x 6 runs/six = 48 runs

       iii. Total runs from boundaries and sixes = 12 + 48 = 60 runs 

The total score was 100 runs, so the runs scored by running between the wickets  are: 

* 100 runs - 60 runs = 40 runs 

To calculate the percentage of the total score made by running, we divide the runs  scored by running (40) by the total score (100) and multiply by 100: * (40 / 100) x 100 = 40%

Solution:

Let the trader purchased 1kg=1000 grams and he sold 10% less means 900 gram instead of 1000 grams. 

Profit % = (Goods left /goods sold) x 100 = 11.11%

Solution:

Total cost of 4 cars =1 + 2 = 3 lakh  

Total S.P of 4 cars =3 × 1.5 = 4.5 lakh 

S.P of 1 car =1.2 lakh 

S.P of rest 3 cars =4.5 − 1.2 = 3.3 lakhs 

Average S.P of all the 3 cars = 1.1 lakhs

Solution:

Let x be the amount of Mangesh. 

Ajay made an item for Rs. 120 and sold it to Vijay at a 25% profit. 25 × 120 = (selling price - 120) × 100

3000 + 12000 = 100 selling price → Selling price = Rs. 150.

Vijay sold it to Ashish who sold it for Rs. 198 making 10% profit.

x × 10% + x = 198 → (x/10) + x → x = 180  

Profit% = (180-150)/150 = 20%

Solution:

Let's assume the initial price of petrol is P and the initial consumption is C. The initial expenditure is P * C. After the 10% increase in price, the new price becomes 1.1 * P. To keep the expenditure constant, the new consumption must be C/(1.1). The percentage reduction in consumption is:  (C - C/(1.1)) / C * 100 = 9.09%

Solution:

Total number of votes polled = (1136 + 7636 + 11628) = 20400 Required % = (11628/20400) * 100 = 57% 

Solution:

Raman's original price be Rs 100 

Decrease by 50 % = 100 − (50/100)  * 100 = 50 

Increase by 50 % = 50 + (50/100) * 50 = 75  

Loss = 100 − 75 = 25 and hence the loss is 25%

Solution:

Total Valid votes = Total votes (1 - 20%) →Valid votes = 7500 (1 - 0.20)→6000 

Total valid votes of one candidate = 60% of valid votes → 3600

Valid vote the other candidate got is → 6000-3600 = 2400

Solution:

Let 1 is the number that is multiplied by 3/4 instead of 4/3 Error Percentage = (4/3 - 3/4)/4/3 × 100 

7/12 × 3/4 × 100 → 43.75

Solution:

36 kilograms of fresh dates contain 0.1 * 36 = 3.6 kilograms of non-water Dry dates obtained from these fresh dates will contain the same amount of  non - water and we are told that this amount should be 72% of the dry dates,  thus x * 0.72 = 3.6 → x = 5 kilograms

Solution:

Offered selling price of first trouser = Rs 42

Actual selling price of first trouser = 42 * (8/7) = Rs 48

Percentage discount on first trouser = ((48-42)/48) * 100 = 12.5 %  Offered selling price of second trouser = Rs 36

Actual selling price of second trouser = (7/6)*36 = Rs 42 

Percentage discount on second trouser = ((42-36)/42) * 100 → 14.28%

Solution:

Since net change is 0 

Successive % change here can be described as : x - y - xy/100 Which is 0 

x - y - xy/100 = 0 → X - Y = XY/100 → 100 (x - y) = xy /100 → xy/ 100 is +ve ,  so x - y should also be +ve  

x>y 

Solution:

Let the total initial cost of production be Rs. 100 

Then, 

manufacturing cost = Rs. 60 

Cost of raw materials = Rs. 40 

Original Selling Price → Rs (100 + (60/4)) → Rs 115 

New cost of raw materials = 130% of Rs. 40 = Rs. 52 

New Manufacturing cost = 120% of Rs. 60 = Rs. 72 

New cost of the product = Rs. (52 + 72) = Rs. 124 

New S.P. = 160% of Rs. 115 → (160/100)/115 →Rs 184 

New profit = Rs. (184 - 124) = Rs. 60 

New profit % → (60/124)*100 →48.39%